Equally far means on the bisector
Every point that is the same distance from X and Y is on one line.
More centres for the eye
One eye used the centres A and B on the line AB. Now choose two other points C and D, also with CX = CY = DX = DY, for a differently shaped eye.
Will C and D lie on the line AB?
What this lesson covers
The idea
A line segment has only one perpendicular bisector, and any point that is at the same distance from X and Y lies on the perpendicular bisector of XY.
More centres for the eye
One eye used the centres A and B on the line AB. Now choose two other points C and D, also with CX = CY = DX = DY, for a differently shaped eye.
Will C and D lie on the line AB?
- Yes, on AB
- No, they can be anywhere
- Only if C and D are at the same distance as A and B
Hunt for equal distances
Drag P around. The gauge shows how far P is from X and from Y. When PX = PY, P clicks onto a line. Pin such points, then use them as centres of eyes.
One line holds them all
Take C and D with CX = CY = DX = DY. The line joining them is the perpendicular bisector of XY (Lesson 2). But XY has only one perpendicular bisector: the line AB. So C and D are on AB.
A line segment has only one perpendicular bisector, and any point at the same distance from X and Y lies on it.
- The point P | Where it is
- PX = PY | on the perpendicular bisector
- PX is less than PY | on X’s side of it
- PX is more than PY | on Y’s side of it
Notes
A line segment has only one perpendicular bisector, and any point that is at the same distance from X and Y lies on it.
Check yourself
A point P is 3 cm from X and 3 cm from Y. Where is P?
A point Q is 2 cm from X and 5 cm from Y. Is Q on the perpendicular bisector of XY?
XY is 10 cm long. P is a point on its perpendicular bisector, and PX + PY = 26 cm. How many cm is PX?
Answer: 13
P is on the perpendicular bisector, so PX = PY. Together they are 26 cm, so PX = 26 ÷ 2 = 13 cm.
Meena says: “I drew two different lines that are both perpendicular bisectors of the same segment XY.” Can she be right?
- On the line XY itself. P could be there only if XY is 6 cm and P is its midpoint. In general it is on the perpendicular bisector.
- On the perpendicular bisector of XY — correct. Yes! PX = PY, so P lies on the perpendicular bisector.
- Nearer to X than to Y. It is exactly as near to X as to Y.
- Yes. Every point near XY is on the bisector.. Being near is not enough. The distances must be equal.
- Yes. It is on the bisector if its distances add up to 7 cm.. The sum does not matter. Only equal distances put a point on the bisector.
- No. It is nearer to X, so it is on X’s side of the bisector. — correct. Yes! Only points with equal distances lie on the perpendicular bisector.
- No. A line segment has only one perpendicular bisector. — correct. Yes! The two lines would have to be the same line.
- Yes, a segment has two: one above and one below.. It is one single line. The parts above and below XY belong to the same line.
- Yes, if the segment is long enough.. The length does not matter. There is exactly one.