Multiples of a multiple
Copies of whole blocks are still whole blocks.
Packets, boxes and orders
A packet holds 7 sweets. A box holds 2 packets, so 14 sweets. A shop orders 5 boxes: 14 × 5 = 70 sweets.
Can all 70 sweets be put back into packets of 7, with none left over?
What this lesson covers
The idea
If A is divisible by k, then all multiples of A are divisible by k.
Packets, boxes and orders
A packet holds 7 sweets. A box holds 2 packets, so 14 sweets. A shop orders 5 boxes: 14 × 5 = 70 sweets.
Can all 70 sweets be put back into packets of 7, with none left over?
- Yes, none left over
- No, some are left over
- It depends on how many boxes are ordered
Make copies
A is built from blocks of 7. Change the blocks in A and the number of copies. Every copy is a group of blocks. What is every total made of?
Copies of multiples
If A is divisible by k, then all multiples of A are divisible by k.
A = k × j, so A × m = (k × j) × m = k × (j × m). It is k times a whole number.
Examples: 28 = (7 × 2) × 2 70 = (7 × 2) × 5 154 = (7 × 2) × 11
Notes
If A is divisible by k, then all multiples of A are divisible by k.
Check yourself
56 is divisible by 7. Which of these must also be divisible by 7?
91 is divisible by 13 (91 = 13 × 7). What is 91 × 6 ÷ 13?
Answer: 42
91 × 6 = (13 × 7) × 6 = 13 × 42 = 546. So 546 ÷ 13 = 42.
6 is not divisible by 4. Which multiple of 6 is not divisible by 4?
27 is divisible by 9. How many of its multiples 27, 54, 81, 108, 135 are divisible by 9?
Answer: 5
27 = 9 × 3, so every multiple 27 × m = 9 × (3 × m) is divisible by 9: 54 = 9 × 6, 81 = 9 × 9, 108 = 9 × 12, 135 = 9 × 15. All 5.
- 56 + 5. 56 + 5 = 61 leaves remainder 5. A multiple of 56 is 56 × m, not 56 + 5.
- 56 × 9 — correct. Yes! 56 × 9 = 504 = 7 × 72. A multiple of a multiple of 7 is a multiple of 7.
- 56 − 3. 56 − 3 = 53 leaves remainder 4. A multiple of 56 is 56 × m, not 56 − 3.
- 56 + 1. 56 + 1 = 57 is one more than a multiple of 7. A multiple of A means A × m, not A + 1.
- 12. 12 = 4 × 3 is divisible by 4.
- 24. 24 = 4 × 6 is divisible by 4.
- 30 — correct. Yes! 30 = 4 × 7 + 2. The rule needs A itself to be divisible by 4. 6 is not, so some multiples of 6 are not.
- 36. 36 = 4 × 9 is divisible by 4.