‹ Class 9 · Ch 5
Exploring Mixtures and their Separation · Principle 3 of 26

Grams in every 100 grams

Mass by mass percentage (% m/⁠m).

Stuck? Ask Guru

NCERT: 5.2.2 How do we express concentration?

Think

Salt in 100 g

You dissolve 10 g of salt in 90 g of water.

About how much of the whole solution is salt?

What this lesson covers

The idea

Mass by mass percentage (% m/m, numerically equal to % w/w) = (mass of solute ÷ mass of solution) × 100, the grams of solute per 100 g of solution, where solution mass = solute mass + solvent mass.

Salt in 100 g

You dissolve 10 g of salt in 90 g of water.

About how much of the whole solution is salt?

  • One tenth of it
  • Nine tenths of it
  • Half of it

Fill the 100 cells

Change the grams of salt and water. Watch the cells. Make 10 % twice.

% m/⁠m

Mass by mass percentage (% m/⁠m or % w/⁠w) = (mass of solute ÷ mass of solution) × 100. It tells how many grams of solute are in 100 grams of the solution. Mass of solution = mass of solute + mass of solvent.

Example 5.1. 10 g of salt is dissolved in 90 g of water. Mass of solution = 10 g + 90 g = 100 g. Percentage = (10 ÷ 100) × 100 = 10 % m/⁠m.

It is also used for spice mixtures, milk powder, and to label salt, sugar or protein in packaged food. % m/⁠m and % w/⁠w are numerically equal.

Notes

% m/⁠m = (mass of solute ÷ mass of solution) × 100: the grams of solute in 100 g of solution.

Check yourself

20 g of salt is dissolved in 80 g of water. What is the mass of the solution?

Answer: 100 g

20 g + 80 g = 100 g.

20 g of salt is dissolved in 80 g of water. What is the mass by mass percentage?

Answer: 20 % m/⁠m

(20 g ÷ 100 g) × 100 = 20 % m/⁠m.

In the % m/⁠m formula, the divisor is the mass of…

5 g of salt is dissolved in 45 g of water. Find the % m/⁠m.

Answer: 10 % m/⁠m

(5 ÷ 50) × 100 = 10 % m/⁠m.

  • the solvent only. Use the whole solution.
  • the solute only. The solute is the top of the fraction.
  • the whole solution — correct. Yes. Solute plus solvent.
Hold to talk

Subscription Status