/ Class 8 · Chapter 13: Factorisation Function Lab

Spotting the Perfect Square

Recognise x^2 + 10x + 25 as (x + 5)^2 and factor it.

Equation
y = (x^2 + 10*x + 25) - (x + 1)^2
Graph
-6-4-20246-120-80-4004080g1g2xy
Table
xy
-5-16
-4-8
-30
-28
-116
024
132
240
348
456
564

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Selina ICSE: Factorisation

What this lesson covers

What you do

You shape the function y = (x^2 + 10*x + 25) - (x + b)^2 and watch the graph answer.

Challenges to clear

  • x² + 10x + 25 is a square in disguise: slide b until (x+b)² matches — 0 at x = 2. (Hint: half of 10.)
  • Confirm at x = −1: it is exactly (x+5)².
  • A perfect square starts with exactly ONE x². Slide a to 1.
  • Now slide b until x² + 12x + 36 matches (x + b)² at x = 2. Halve the 12 — and check 36 really is that half squared.

Check yourself

Why does the graph staying flat at y=0 prove that x^2 + 2ax + a^2 = (x+a)^2?

Which of the following is a perfect square trinomial?

If a = 4, what is the value of the middle term 2ax when x = 3?

  • Because the difference between the two sides is always zero, meaning they are equal for all x and a. — correct
  • Because the graph is a straight line.
  • Because x^2 is always positive.
  • Because the slider only goes up to 5.
  • x^2 + 6x + 9 — correct
  • x^2 + 6x + 6
  • x^2 + 9x + 3
  • x^2 + 6x + 12
  • 24 — correct
  • 12
  • 7
  • 16

Think about it

  • x² + 10x + 25: half of 10 is…?
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