/ Class 8 · Chapter 9: Interest (Simple and Compound) Function Lab

Cracking the SI Formula

Use inverse operations to find Principal, Rate, or Time from the Simple Interest formula.

Equation
y = x * (5/100) * 1
Graph
4k8k12k16k20k-1k1k3k5k7k9k11k13kg1g2xy
Table
xy
5000250
7500375
10000500
12500625
15000750
17500875
200001000

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Selina ICSE: Interest (Simple and Compound)

What this lesson covers

What you do

You shape the function y = x * (r/100) * t and watch the graph answer.

Challenges to clear

  • Verify the calculation: With r=10 and t=3, does a Principal of 15000 yield an Interest of 4500? Check the table row for x=15000.
  • Confirm the relationship: If the Principal is 10000, the interest should be 3000 (10% of 10000 × 3 years).
  • A longer loan: slide the time t to 4 years.
  • Now the rate: a principal of 20000 must earn 4000 over those 4 years. Simple interest never compounds — each year earns the same.

Check yourself

If SI = 4500, R = 10%, and T = 3 years, which algebraic step correctly isolates the Principal P?

Why do we divide the Simple Interest by the product of Rate and Time (R*T/100) to find the Principal?

  • P = 4500 / (10 * 3)
  • P = 4500 / (0.10 * 3) — correct
  • P = 4500 * 0.10 * 3
  • P = 4500 / 0.10 / 3
  • Because Principal is the result of multiplying Interest by Rate and Time.
  • Because Interest is calculated as P * (R*T/100), so we reverse the multiplication by dividing. — correct
  • Because Rate and Time are subtracted from the Principal to get Interest.
  • Because the formula requires adding Rate and Time before dividing.

Think about it

  • We need the Principal (x) that produces Rs 4500 interest at r = 10% over t = 3 years. Which table row will show 4500?
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