Rationalise 1/(2 + √3)
Multiply by the conjugate to clear the surd from the denominator.
Equation
y = x * (1/(2 + sqrt(3)) - (0 - sqrt(3)))
Graph
Table
| x | y |
|---|---|
| 0 | 0 |
| 1 | 2 |
| 2 | 4 |
| 3 | 6 |
| 4 | 8 |
What this lesson covers
What you do
You shape the function y = x * (1/(2 + sqrt(3)) - (k - sqrt(3))) and watch the graph answer.
Challenges to clear
- The conjugate says 1/(2+√3) = k − √3 for some whole k. Slide k until the difference is 0 at x = 1.
- Still 0 at x = 3 — so 1/(2+√3) = 2 − √3 exactly.
- Same move, harder numbers: 1/(4+√15). The conjugate (4−√15) makes the denominator 4² − 15 = 1. The answer is p − q√15 — slide q to how many √15 are left.
- Now slide p until the difference is 0 at x = 1 — so 1/(4+√15) = 4 − √15, a fraction with no root below the bar.
Check yourself
Why do we multiply by the conjugate?
- Because (a + b)(a - b) = a^2 - b^2, which removes the square root if b is a surd. — correct
- Because it makes the numerator larger and easier to read.
- Because we must always multiply the top and bottom by the same number.
- Because it changes the value of the fraction to a rational number.
Think about it
- Multiply 1/(2+√3) by (2−√3)/(2−√3). The denominator becomes 4 − 3 = 1. What is left on top?