/ Class 9 · Chapter 1: Rational and Irrational Numbers Function Lab

Multiply Surds: Root of Product

See why root 2 times root 3 becomes root 6.

Equation
y = sqrt(2) * sqrt(x) - sqrt(5*x)
Graph
-113579-7-5-3-11357g2xy
Table
xy
00
1-0.82
2-1.16
3-1.42
4-1.64
5-1.84
6-2.01
7-2.17
8-2.33
9-2.47

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Selina ICSE: Rational and Irrational Numbers

What this lesson covers

What you do

You shape the function y = sqrt(m) * sqrt(x) - sqrt(k*x) and watch the graph answer.

Challenges to clear

  • √m · √x = √(m·x): with m = 2, slide k to match — the difference is 0 at x = 3 only when k = m.
  • Check x = 2 as well: √2·√2 = √4 = 2. Root times root is root of the product.
  • Now the product runs the other way: √(3m·x) has to match √(k·x). Start by sliding m to 5.
  • With m = 5 the left side is √3·√5·√x. Slide k until the difference is 0 at x = 4 — root times root is the root of the product, so k = 15.

Check yourself

Which rule correctly explains why sqrt(5) * sqrt(7) = sqrt(35)?

  • sqrt(a) * sqrt(b) = sqrt(a * b). Multiply the numbers under the root. — correct
  • sqrt(a) * sqrt(b) = sqrt(a + b). Add the numbers under the root.
  • sqrt(a) * sqrt(b) = a * b. Remove the roots completely.
  • sqrt(a) * sqrt(b) = sqrt(a) + sqrt(b). Keep roots separate but add them.

Think about it

  • √2 × √3 — is it √5 or √6?
Hold to talk

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