Excess Alkali Mystery
Why do some precipitates dissolve in excess NaOH?
What this lesson covers
Why it matters
A white precipitate of zinc hydroxide does not dissolve when only a little sodium hydroxide is added, but vanishes completely when you add excess sodium hydroxide.
The idea in plain words
Map the atoms: show how Zn(OH)₂ and NaOH rearrange to form Na₂ZnO₂ and water.
Predict first
Why does the white Zn(OH)₂ precipitate dissolve in excess NaOH?
Zinc hydroxide is amphoteric: it acts as an acid towards strong bases like NaOH, forming soluble sodium zincate.
- It is an amphoteric hydroxide reacting to form a soluble salt — correct
- The heat from mixing melts the solid
- NaOH is a solvent that dissolves all solids
- The precipitate evaporates into the solution
What you do
Add excess NaOH to both Zn(OH)₂ and Pb(OH)₂. Observe which precipitates dissolve and note the clear solutions formed.
Check yourself
What is the chemical formula of the soluble salt formed when Zn(OH)₂ dissolves in excess NaOH?
The reaction Zn(OH)₂ + 2NaOH → Na₂ZnO₂ + 2H₂O produces sodium zincate (Na₂ZnO₂).
Which condition is strictly required for Pb(OH)₂ to dissolve in NaOH according to the reaction data?
The reaction data for Pb(OH)₂ + 2NaOH → Na₂PbO₂ + 2H₂O specifies 'conc': 'excess' as a condition.
Why does Zn(OH)₂ dissolve when excess NaOH is added?
Zn(OH)₂ is amphoteric: with excess strong alkali it behaves as an acid, reacting with NaOH to form the soluble salt sodium zincate, Na₂ZnO₂.
- Na₂ZnO₂ — correct
- ZnNaO₂
- NaZn(OH)₄
- Zn(OH)₄
- Excess concentration of NaOH — correct
- Heating the mixture
- Presence of light
- Electrolysis
- It is an amphoteric hydroxide reacting with excess alkali to form a soluble salt (sodium zincate) — correct
- The strong alkali simply melts the solid precipitate
- NaOH acts as a universal solvent that dissolves every precipitate
- The precipitate reacts with water to evaporate away