Heights and Distances

353. The Sun's Shadow Angle · how height and shadow reveal the sun's elevation

tan(θ) = height / shadow length.

TBh√3 hθ = 30°θ = 30°S
For a vertical object and its shadow on level ground, the sun's angle of elevation θ satisfies tan θ = height / shadow length. A higher sun (larger θ) casts a shorter shadow.

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Selina ICSE: Heights and Distances

What this lesson covers

Try to break it

Drag S closer to the tower and the shadow shortens — θ grows toward 90° (sun overhead). Drag S far away and the shadow stretches — θ drops toward 0° (sun on the horizon). When the shadow equals h·√3, θ = 30°; when it equals h, θ = 45°; when it equals h/√3, θ = 60°.

The proof, step by step

Prove that tan θ equals the height divided by the shadow length.

  • Let the tower height TB = h.
  • Given the shadow length BS = √3 h.
  • In right ΔTBS, tan S = TB / BS = h / (√3 h) = 1 / √3.
  • We know that tan 30° = 1 / √3.
  • Therefore, the angle of elevation S = 30°.

Worked example

A pole 10 m high casts a shadow 10√3 m long. What is the angle of elevation of the sun?

tan θ = height/shadow = 10/(10√3) = 1/√3. Since tan 30° = 1/√3, θ = 30°.

  • 30° — correct
  • 45°
  • 60°
  • 90°
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