Constructions

57. The Angle Splitter · cutting any angle perfectly in half

OE always splits ∠AOB into two equal angles, no matter how you drag the arms.

CDE∠AOE = 34°∠AOE = 34°∠EOB = 34°∠EOB = 34°OAB
To bisect an angle with compass and straightedge: from O, draw an arc cutting both arms at equal distances. From those two intersection points, draw equal arcs that meet at E. The line OE bisects ∠AOB into two equal halves.

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Selina ICSE: Constructions

What this lesson covers

Try to break it

What if we change the angle itself? Drag O, A, or B to reshape the angle, and see how the bisector OE always stays perfectly balanced!

How you build it

Construct the bisector of an angle.

  • Mark point O — the vertex of the angle.
  • Draw a ray from O — the first arm.
  • Draw a second ray from O — the other arm. This is the angle to bisect.
  • With centre O, draw an arc that cuts both arms.
  • Mark point C where the arc cuts the first arm.
  • Mark point D where the arc cuts the other arm.
  • With the same opening and centre C, draw an arc inside the angle.
  • With the same opening and centre D, draw an arc crossing the one from C.
  • Mark point E where the two arcs cross.
  • Draw the ray OE — it bisects the angle into two equal halves.

The proof, step by step

Prove that ray OE divides ∠AOB into two equal angles.

  • In ΔOCE and ΔODE, OC = OD (radii of the same arc drawn from O).
  • CE = DE (arcs drawn with equal radii from C and D).
  • OE = OE (common side).
  • Therefore, ΔOCE ≅ ΔODE by SSS congruence rule.
  • Hence, ∠COE = ∠DOE (c.p.c.t.).
  • So, OE bisects ∠AOB.

Worked example

In the construction of the bisector of ∠AOB, arcs are drawn from C and D with equal radii. Why must this radius be more than half of CD?

If the radius is less than or equal to half of CD, the arcs from C and D will not intersect. We need point E to draw the bisector OE.

  • To make the drawing look neater
  • So that the two arcs intersect each other — correct
  • To ensure the compass doesn't slip
  • It does not matter what the radius is
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