Congruency: Congruent Triangles

129. RHS Congruence Criterion · Right angle, Hypotenuse, Side

If hypotenuse and one side match, the triangles are congruent.

ABCFDAC = 250AC = 250FD = 250FD = 250AB = 200AB = 200FE = 200FE = 200E
RHS congruence test (Right-angle Hypotenuse Side): two right triangles are congruent if their hypotenuses are equal AND one pair of legs is equal. The third side and remaining angles are then determined by Pythagoras.

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Selina ICSE: Congruency: Congruent Triangles

What this lesson covers

Try to break it

Drag E along the base. The blue right triangle stretches, but its hypotenuse and one leg stay locked equal to the red triangle's. Try to make the two triangles non-congruent — impossible. RHS holds.

How you build it

Construct two right triangles by RHS.

  • Draw a line segment AB, the first leg of the right triangle.
  • At B, draw a line perpendicular to AB.
  • Mark point C on the perpendicular so that BC equals the given length.
  • Draw segment AC to form the hypotenuse of the first triangle.
  • Draw a line segment DE, the first leg of the second right triangle.
  • At E, draw a line perpendicular to DE.
  • Mark point F on the perpendicular so that EF equals BC.
  • Draw segment DF to form the hypotenuse of the second triangle.

The proof, step by step

Prove that an equal hypotenuse and one side make right triangles congruent (RHS).

  • In ΔABC and ΔFED, ∠B = ∠E = 90° (Given)
  • AC = FD (Given, hypotenuse)
  • AB = FE (Given, side)
  • ∴ ΔABC ≅ ΔFED (by RHS Congruence Rule)

Worked example

In ΔABC and ΔDEF, ∠B = ∠E = 90°, AC = DF = 10 cm, and BC = EF = 6 cm. Which congruence criterion proves ΔABC ≅ ΔDEF?

Both triangles are right-angled at B and E. The hypotenuses (AC and DF) are equal, and one pair of corresponding legs (BC and EF) are equal. Therefore, ΔABC ≅ ΔDEF by the RHS congruence criterion.

  • SAS
  • ASA
  • RHS — correct
  • SSS
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