Special Types of Quadrilaterals

172. The Kite's Balance · adjacent sides equal, diagonals perpendicular

Diagonals are always perpendicular, and AC always bisects BD.

OABCD∠BOC = 90°∠BOC = 90°OB = 120OB = 120OD = 120OD = 120
A kite is a quadrilateral with two pairs of adjacent sides equal. Its diagonals are perpendicular to each other, and the longer diagonal bisects the shorter at right angles.

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Selina ICSE: Special Types of Quadrilaterals

What this lesson covers

Try to break it

Drag A up and C down to set the vertical diagonal; drag B and D out to set the horizontal half-diagonals. As long as B and D stay equidistant from the centre, AB = AD and CB = CD and the kite keeps its symmetry. Pull B and D to unequal distances and the kite breaks — the adjacent-sides equality fails.

How you build it

Construct a kite from perpendicular diagonals.

  • Draw segment BD, the horizontal diagonal of the kite.
  • Construct the perpendicular bisector of BD; it crosses BD at O.
  • Mark point A on the bisector above BD.
  • Mark point C on the bisector below BD, with OC different from OA.
  • Draw segment AB of the kite.
  • Draw segment BC of the kite.
  • Draw segment CD of the kite.
  • Draw segment DA to complete the kite.

The proof, step by step

Prove that the diagonals of a kite are perpendicular and one bisects the other.

  • In ΔABD, AB = AD (given). Thus, ΔABD is isosceles.
  • In ΔCBD, CB = CD (given). Thus, ΔCBD is isosceles.
  • Points A and C are both equidistant from B and D, so AC is the perpendicular bisector of BD.
  • Therefore, AC ⊥ BD and OB = OD.
  • By SSS, ΔABC ≅ ΔADC, giving ∠ABC = ∠ADC and AC bisects ∠BAD and ∠BCD.

Worked example

In a kite ABCD, diagonals intersect at O. If AC = 10 cm and BD = 8 cm, what is the area of the kite?

Area of a kite = ½ × d₁ × d₂ = ½ × 10 × 8 = 40 cm².

  • 20 cm²
  • 40 cm² — correct
  • 80 cm²
  • 160 cm²
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