Special Types of Quadrilaterals
166. The Parallelogram's Balance · Opposite sides & angles always match
Opposite sides are equal, opposite angles match, and diagonals bisect each other.
The Parallelogram Theorem has four parts: (1) opposite sides are equal, (2) opposite angles are equal, (3) adjacent angles are supplementary (sum to 180°), and (4) diagonals bisect each other. All four hold simultaneously for any parallelogram.
What this lesson covers
Try to break it
Drag A, B, or D. The shape stretches and shears, but AB ∥ DC, AD ∥ BC, opposite sides stay equal, and opposite angles stay equal. Try to drag a vertex so one pair of opposite sides stops being parallel — the figure refuses; the fourth vertex follows along to keep the parallelism.
How you build it
Construct a parallelogram.
- Place point A — the first corner of the base.
- Place point B — the second corner of the base.
- Draw segment AB — the base of the parallelogram.
- Place point D above AB — the third corner.
- Draw segment AD — one slant side of the parallelogram.
- Parallel tool: click point B, then click side AD — draws the line through B parallel to AD. Side BC will lie on it.
- Parallel tool: click point D, then click base AB — draws the top side DC parallel to AB.
- Mark point C where the two parallel lines cross — click snaps to the exact crossing. AB ∥ DC and AD ∥ BC by construction.
The proof, step by step
Prove that opposite sides and opposite angles of a parallelogram are equal and its diagonals bisect each other.
- Draw diagonal AC to split the parallelogram into ΔABC and ΔADC.
- ∠BAC = ∠DCA (Alternate angles, AB || DC)
- ∠BCA = ∠DAC (Alternate angles, AD || BC)
- AC = AC (Common side)
- ΔABC ≅ ΔADC by ASA congruence rule.
- Therefore, AB = DC, BC = AD, and ∠B = ∠D (CPCT).
Worked example
In a parallelogram ABCD, if ∠A = 70°, find the measure of ∠C and ∠B.
Opposite angles of a parallelogram are equal, so ∠C = ∠A = 70°. Adjacent angles are supplementary, so ∠B = 180° - 70° = 110°.
- ∠C = 70°, ∠B = 110° — correct
- ∠C = 110°, ∠B = 70°
- ∠C = 70°, ∠B = 70°
- ∠C = 110°, ∠B = 110°