Rectilinear Figures [Quadrilaterals: Parallelogram, Rectangle, Rhombus, Square and Trapezium]
236. The Parallelogram Key · One pair equal & parallel unlocks the shape
Opposite sides AD and BC remain equal and parallel as you drag.
A quadrilateral is a parallelogram if one pair of opposite sides is both equal and parallel. Once AD = BC and AD ∥ BC, the figure is forced to be a parallelogram, so the other pair of sides is equal and parallel as well.
What this lesson covers
Try to break it
Drag A, B, or D. The construction holds AB = DC and AB ∥ DC at all times — and the moment those two conditions are true on one pair of sides, the other pair (AD and BC) automatically becomes parallel and equal too. Try to find a shape where AD and BC tilt apart; impossible.
How you build it
Construct a parallelogram ABCD.
- Point tool: mark point A.
- Point tool: mark point B.
- Point tool: mark point D, off the line AB.
- Segment tool: join A to B — one pair of opposite sides.
- Parallel tool: click D, then line AB — a line through D parallel to AB (it carries side DC).
- Compass tool: click A then B to open the compass exactly to the length AB.
- Compass tool: keep the opening and click D — an arc of radius AB swings from D and crosses the parallel line.
- Point tool: mark C where that arc meets the parallel line. Now DC = AB and DC ∥ AB.
- Segment tool: join A to D.
- Segment tool: join B to C — notice AD and BC come out equal and parallel too.
The proof, step by step
Prove that a quadrilateral with one pair of opposite sides equal and parallel is a parallelogram.
- ∠1 = ∠2 (Alternate angles, since AB // DC and AC is transversal)
- AB = DC (Given)
- AC = AC (Common side)
- ΔABC ≅ ΔCDA (By SAS Congruence)
- ∠3 = ∠4 (CPCT - Corresponding Parts of Congruent Triangles)
- AD // BC (If alternate angles are equal, lines are parallel)
- ABCD is a parallelogram (Both pairs of opposite sides are parallel)
Worked example
In a quadrilateral ABCD, AB = DC and AB // DC. If ∠BAC = 35°, find the measure of ∠DCA.
Since AB // DC and AC is a transversal, alternate angles ∠BAC and ∠DCA are equal. Therefore, ∠DCA = ∠BAC = 35°.
- 35° — correct
- 45°
- 55°
- 70°