Co-ordinate Geometry

285. Plotting the Line · Connecting points to reveal the graph

Point P always lies on the line y = mx + c.

xyOy = 2x + 1A(-1, -1)B(0, 1)C(1, 3)-6-4-2-1123464321-1-2-3P = (0.6, 2.2)P = (0.6, 2.2)
To graph a linear equation y = mx + c, find a few points that satisfy it, plot them, and join them with a ruler. Because the equation is linear, the points always lie on one straight line.

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Selina ICSE: Co-ordinate Geometry

What this lesson covers

Try to break it

Drag P along the line. At every position the coordinates satisfy y = 2x + 1 — try to find a P on the line where they don't. Now imagine pulling P to (5, 3): that point sits off the line because 2(5) + 1 = 11 ≠ 3. Only points whose coordinates satisfy the equation belong on the graph.

How you build it

Plot points of y = 2x + 1 and join them into a line.

  • Point tool: plot A at (-1, -1) — a point that satisfies y = 2x + 1.
  • Point tool: plot B at (0, 1) — the y-intercept.
  • Point tool: plot C at (1, 3).
  • Line tool: click A, then C — the straight line passes through all three points. They are collinear because y = 2x + 1 is linear.

The proof, step by step

Prove that point P lies on the line y = mx + c.

  • The graph of a linear equation is a straight line.
  • Any point on the line satisfies the equation.
  • The equation is satisfied by the coordinates of any point on the line.

Worked example

Draw the graph of the equation y = 3x - 2. From the graph, find the value of y when x = 2.

Substitute x = 2 into the equation: y = 3(2) - 2 = 6 - 2 = 4.

  • 4 — correct
  • 6
  • 8
  • 2
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