210. The RHS Rule · Hypotenuse & side guarantee congruence
If two right triangles have equal hypotenuse and one leg, they are always congruent.
What this lesson covers
Try to break it
Drag C along the horizontal base. Both triangles' bases stretch together, keeping the hypotenuse and the right-angle leg matched. Try to drag C to a length where one triangle differs from the other — you can't, the handle drives both. RHS holds.
How you build it
Construct two right triangles with equal hypotenuse and one leg to test the RHS rule.
- Point tool: mark point B — the right-angle corner.
- Point tool: mark point A above B — BA is the given leg.
- Segment tool: join B to A. This is one leg.
- Perp tool: click B (on leg BA), then click to the side — this raises the right angle at B; the base BC lies on this perpendicular.
- Point tool: mark point C on the perpendicular, a little way out from B. You pick the spot — BC is the second leg and AC will be the hypotenuse you copy later.
- Now the second triangle. Point tool: mark point E to the right — its right-angle corner.
- Ray tool: click E, then click upward — leg ED will lie on this ray.
- Arc tool: click centre B, drag until the arc snaps to A. This locks the radius to the leg BA.
- Arc tool: click centre E — with BA locked, the arc crosses the leg ray at D, so ED = BA.
- Point tool: mark D where the arc meets the leg ray.
- Segment tool: join E to D.
- Perp tool: click E (on leg ED), then click to the side to raise the right angle at E.
- Arc tool: click centre A, drag until the arc snaps to C. This locks the radius to the hypotenuse AC.
- Arc tool: click centre D — with AC locked, the arc crosses the perpendicular at F, so DF = AC.
- Point tool: mark F where the arc meets the perpendicular.
- Segment tool: join D to F. Right angle at E, leg ED = BA, hypotenuse DF = AC — so triangle DEF is congruent to ABC by RHS.
The proof, step by step
Prove that an equal hypotenuse and one leg make right triangles congruent (RHS).
- ∠B = ∠E = 90° (Given)
- AC = DF (Hypotenuse, Given)
- AB = DE (Side, Given)
- ∴ ΔABC ≅ ΔDEF (By RHS Congruence Rule)
Worked example
In right ΔPQR and ΔXYZ, ∠Q = ∠Y = 90°. PR = 13 cm, PQ = 5 cm, and XY = 5 cm. If ΔPQR ≅ ΔXYZ by RHS rule, what is the length of YZ?
Since ΔPQR ≅ ΔXYZ by RHS, corresponding sides are equal. PQ = XY = 5 cm. PR = XZ = 13 cm. By Pythagoras theorem, YZ = √(XZ² - XY²) = √(169 - 25) = √144 = 12 cm.
- 5 cm
- 12 cm — correct
- 13 cm
- 8 cm