‹ Class 10 · Ch 5
Arithmetic Progressions · Principle 7 of 12

Count the steps from the first term

The nth term is aₙ = a + (n − 1)d.

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NCERT: 5.3 nth Term of an AP

Think

Reena's salary again

Reena's salary is ₹8000 in year 1 and goes up by ₹500 every year.

Year 2: 8000 + 500. Year 3: 8000 + 500 + 500 = 8000 + 2 × 500. Year 4: 8000 + 3 × 500.

How many ₹500 raises have been added by the 15th year?

What this lesson covers

The idea

The nth term (general term) of an AP with first term a and common difference d is aₙ = a + (n – 1)d; in an AP of m terms, aₘ is the last term, also denoted l.

Reena's salary again

Reena's salary is ₹8000 in year 1 and goes up by ₹500 every year.

Year 2: 8000 + 500. Year 3: 8000 + 500 + 500 = 8000 + 2 × 500. Year 4: 8000 + 3 × 500.

How many ₹500 raises have been added by the 15th year?

  • 15
  • 14
  • 16

How many steps to reach a term?

The first block is a. Each d block is one step. Move n and look at how many d blocks there are. Find the term of this AP that equals the target.

The nth term

aₙ = a + (n − 1)d is the nth term (or general term) of an AP with first term a and common difference d.

To go from the 1st term to the nth term you take n − 1 steps of d: 10 terms means 9 steps. For the AP 2, 7, 12, …: a₁₀ = 2 + 9 × 5 = 47.

If an AP has m terms, aₘ is its last term. It is sometimes written *l* (a small letter L).

Notes

aₙ = a + (n − 1)d: the nth term is the first term plus n − 1 steps of d. The last term of an AP with m terms is aₘ, also written *l*.

Check yourself

An AP has 12 terms. Which one is its last term, *l*?

Reena earns ₹8000 in year 1, with a raise of ₹500 each year. What is her monthly salary (in ₹) in the 25th year?

Answer: 20000

a₂₅ = 8000 + (25 − 1) × 500 = 8000 + 12000 = 20000.

Which term of the AP 21, 18, 15, … is −81?

Answer: 35

−81 = 21 − 3(n − 1), so −102 = −3(n − 1), so n − 1 = 34 and n = 35.

Is 301 a term of the list 5, 11, 17, 23, …?

  • a₁₂ — correct. Yes! With 12 terms, the last one is the 12th term, a₁₂. It is also written *l*.
  • a₁₁. a₁₁ is the second-last term. The last of 12 terms is a₁₂.
  • a. a is the first term.
  • No. 301 = 5 + (n − 1) × 6 gives n = 151/3, which is not a whole number. — correct. Yes! The position n must be a whole number, and 151/3 is not.
  • Yes. It is the 50th term.. Check: a₅₀ = 5 + 49 × 6 = 299, not 301.
  • Yes. The list grows, and 301 is bigger than 5.. Being bigger is not enough. The list has to hit 301 exactly, at a whole-number position.
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