‹ Class 9 · Ch 5
I'm Up and Down, and Round and Round · Principle 12 of 26

Centre to the middle

Centre to the midpoint of a chord

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NCERT: 5.5 Midpoints and Perpendicular Bisectors of Chords

Think

A line to the middle

Draw a chord AB of a circle and find its midpoint M. Now draw the line from the centre O to M.

How does the line OM meet the chord AB?

What this lesson covers

The idea

The line joining the centre of a circle to the midpoint of a chord is perpendicular to the chord.

A line to the middle

Draw a chord AB of a circle and find its midpoint M. Now draw the line from the centre O to M.

How does the line OM meet the chord AB?

  • At a right angle
  • At 60°
  • At an angle that changes from chord to chord

Measure the angle

M is always the midpoint of AB. Drag A and B round the circle to make different chords, and read ∠OMB.

Always 90°

The line joining the centre of a circle and the midpoint of a chord is perpendicular to the chord.

In triangles OMA and OMB, OA = OB (radii), AM = MB (M is the midpoint) and OM is common. So they are congruent (SSS) and ∠OMA = ∠OMB. These two angles lie along the straight line AB, so they add up to 180°. Each one is 90°.

Notes

The line joining the centre of a circle to the midpoint of a chord is perpendicular to the chord.

Check yourself

M is the midpoint of chord AB of a circle with centre O. What is ∠OMA, in degrees?

Answer: 90 °

The line from the centre to the midpoint of a chord is perpendicular to the chord, so ∠OMA = 90°.

M is the midpoint of chord AB, and O is the centre. Why is ∠OMA = ∠OMB?

M is the midpoint of chord AB of a circle with centre O. AM = 4 cm and OM = 3 cm. What is the radius OA, in cm?

Answer: 5 cm

OM is perpendicular to AB, so triangle OMA is right-angled at M. OA² = 3² + 4² = 25, so OA = 5 cm.

AB is a diameter of a circle with centre O. Where is the midpoint of AB?

  • Because AB is a diameter. If AB were a diameter, M would be the centre O. There is no triangle OMA then.
  • Triangles OMA and OMB are congruent (SSS) — correct. Yes. OA = OB, AM = MB and OM is common to both triangles.
  • Because OM = AM. Nothing says OM and AM are equal.
  • Halfway between O and the circle. The midpoint of a diameter is the centre itself.
  • On the circle. The ends A and B are on the circle. The midpoint is the centre.
  • At the centre O — correct. Yes. A diameter passes through the centre, and the centre is its midpoint.
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